Solve the simultaneous equation 6x + 2y = -3, 4x - 3y =11

6x + 2y = -3 (1)*3 4x - 3y = 11 (2)*2 18x + 6y = -9 (1) 8x - 6y = 22 (2) (1) + (2) = 18x +8x + 6y - 6y = -9 + 22 => 26x = 13 => x = 1/2 sub x into (1) => (6 * 0.5) + 2y = -3 3 + 2y = -3 2y = -6 y = -3

AP
Answered by Aldouz P. Maths tutor

8895 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I use Pythagorus' Theorum?


What is Pythagoras' Theorem and how do I use it?


Bill buys 8 identical cricket balls. The total cost is £169.04 Work out the total cost of 19 of these cricket balls. (Calculator allowed).


Write 0.319319... as a fraction in its lowest terms


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning