Find the value of the discriminant of x2 + 6x + 11

For a quadratic equation in the form ax^2+bx+c=0 the determinant is given by b^2-4ac and is used to help identify the types of roots of the equation. In this case, the determinant is (6)^2-4(1)(11) which is equal to -8.

EC
Answered by Emily C. Maths tutor

8726 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Using the substitution of u=6x+5 find the value of the area under the curve f(x)=(2x-3)(6x+%)^1/2 bounded between x=1 and x=1/2 to 4 decimal places.


Why do we need to differentiate?


How would you determine what sort of stationary point this curve has? x^3 - 6x^2 + 9x - 4


What is dot product and how to calculate it?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning