How do I integrate and differentiate 1/(x^2)?

1/(x²) can be written as x^-2

We know that to differentiate you need to multiply by the value of the old power and minus 1 from it. This means dy/dx of y=x^-2 is -2x^-3=-2/(x³)

To integrate you add one to the power and divide by the new power and add a constant. So the integral is (1/-1)x^-1+c=-1/x + c