Prove 2^n >n for all n belonging to the set of natural numbers

for n=1 2^1=2  2>1 hence true for n=1 assume true for n then 2^n >n we need to show 2^n+1 > n+1 since 2^n >n 2^n+1 >2n =n+n >n+1 for n>1 hence by induction since true for n= 1 and if true for n then true for n+1 the statement is true for all natural numbers

Answered by Matthew M. Maths tutor

3079 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Use integration to find I = ∫ xsin3x dx


If I have the equation of a curve, how do I find its stationary points?


Given that y=π/6 at x=0 solve the differential equation,dy/dx=(e^x)cosec2ycosecy


Find the gradient of the tangent to the curve with the equation y = (3x^4 - 18)/x at the point where x = 3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences