Simultaneously solve the equations 3x+2y=36 and 5x+4y=64

The easiest way to solve a simultaneous equation is by the method of substitution. First of all, we take the first equation, and rearrange it so that it is in terms of y. Or, in other words, rearrange it so that it becomes y=something, as shown below. 3x+2y=36 Subtracting 3x from both sides and then dividing both sides by 2 gives us: y=18-1.5x We then substitute this into the second equation, in place of y. Giving us: 5x+4(18-1.5x)=64 Multiplying out of the brackets gives us. 5x-6x+72=64 Which, with simplification, and 72 subtracted from both sides, gives us: -x=-8 which is the same as x=8. Then, all we need to do in put this value of x into either of the original equations, giving us y=6.

Answered by Finlay S. Maths tutor

9707 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A ladder 5m long is leaning up against a wall. The foot of the ladder is 3m from the wall. How high up the wall does the ladder reach?


How do I work out the exact value of a number which is expressed as an indice, for example 81^-1/4


How can I work out the area of a semi-circle with a diameter of 12cm?


Bob earns £7.70 an hour, and he works 30 hours per week. If Bob has 28 days of unpaid holidays to take, how much does he earn in a year? Also will he be taxed? (Bob will be taxed if he earns over £10000 in one year)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences