x = t^3 + t, y = t^2 +1, find dy/dx
dy/dx = dy/dt x dt/dx
x = t3 + t
dx/dt = 3t2 +1
y = t2 +1
dy/dt = 2t
dy/dx = 2t x (1 / (3t2 +1) )
= 2t / (3t2+ 1)
SK
dy/dx = dy/dt x dt/dx
x = t3 + t
dx/dt = 3t2 +1
y = t2 +1
dy/dt = 2t
dy/dx = 2t x (1 / (3t2 +1) )
= 2t / (3t2+ 1)
