Differentiate the following: 7x^2 - 3x^3 + 5 + 27x

To solve this, we mutiply the powers by their respective co-efficients, then we lower the power by 1. If there isn't any X value following the number, we ignore the number entirely because it is a constant.  So, 7 mutiplied by 2 = 14  This gives us 14x^2-1 = 14x  -3 multiplied by 3 = -9  This gives us -9x^3-1 = -9x^2 We ignore the 5 as it is a constant (there is no X value following it)  27x is the same as 27x^1, so if we mutiply the power by the co-efficient and lower the power, we are simply left with 27.  The final answer will thus read: -9x^2 +14x +27

OS
Answered by Oliver S. Maths tutor

2843 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you use the completing the square method to solve a quadratic equation?


given that f(x) = x^4 + 2x, find f'(x)


Ian earns £420 a week after a 5% rise. What was his pay before?


Find the value of x that satisfies the following equation: (3x + 2)/2 = 6x + 4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences