Solve the following simultaneous equations: (1) 4x+y=7 and (2) 3x+2y=9

This question can be answered by the elimination method. I will choose to eliminate 'y' in this case. Firstly, multiply equation (1) by 2, resulting in 8x+2y=14. Now we can subtract eqaution (2): 3x+2y=9 from equation (1): 8x+2y=14. This results in 5x=5, showing we have eliminated 'y'. Both sides of the equation can be divided by 5. giving x=1. Next, substitute x=1 into equation (1): 41+y=7, so y=3. This means the answer is x=1 and y=3. To check our answer is correct, substitute these values for x and y into equation (2): 31+2*3=9, which gives 9=9 showing us that our answer is correct.

Answered by Alex D. Maths tutor

5019 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

You are told that a straight line runs through 2 points: (1,1) and (2,3). What is the equation of the line?


Calculate 3/5 + 5/8. Give your answer as a mixed number in its simplest form.


Factorise and solve the quadratic equation x^2 + 6x + 8 = 0


Can you solve (2x-4)(x+1)=0?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences