solve the simultaneous equations 3x+7y=18 and 7x+9y=8

3x+7y=18 (eqn 1)  -multiply by 7->   21x+49y=126 (eqn 1*)

7x+9y=8  (eqn 2)  -multiply by 3->    21x+27y=24 (eqn 2*)

(eqn 1*)-(eqn 2*)  --> 22y=102 therefor y=51/11

sub in this y value back into (eqn1) -->  3x+7(51/11)=18 --> 3x+357/11=18 --> 3x=-159/11

therefore x=-53/11

RS
Answered by Radhika S. Maths tutor

3729 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the equation 7x + 6 = 1 + 2x


solve to 2 decimal places; (2x+3/(x-4)) - 2x-8/(2x+1) = 1


Solve the simultaneous equation, 3x + y = 8 and x + 3y = 12, to find a value for x and y.


What is the value of 64^(2/3)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning