solve the simultaneous equations 3x+7y=18 and 7x+9y=8

3x+7y=18 (eqn 1)  -multiply by 7->   21x+49y=126 (eqn 1*)

7x+9y=8  (eqn 2)  -multiply by 3->    21x+27y=24 (eqn 2*)

(eqn 1*)-(eqn 2*)  --> 22y=102 therefor y=51/11

sub in this y value back into (eqn1) -->  3x+7(51/11)=18 --> 3x+357/11=18 --> 3x=-159/11

therefore x=-53/11

RS
Answered by Radhika S. Maths tutor

3600 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

which expression is equivalent to x^2-4? (x-2)^2 (x-2)(x+2) (x+2)(x+2) x^2(-4)


y is inversely proportion to the square of x. y=10 when x=5. Express y in terms of x.


Solve the simultaneous equations: y = 4x^2 - 9x - 1 and y = 5 - 4x


Solve the equation ((2x+3)/(x-4))-((2x-8)/(2x+1))=1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning