What is the equilibrium constant?

Imagine a bathtub that someone forgot to plug, but they left the tap open. If the water from the tap is running fast enough, after some time the speed at which water drains and the speed at which water fills the bathtub will equalibrate, and the water level inside the bathtub will remain constant. Although the system is constantly changing ('new' water flowing in and 'old' water draining), you can't notice it as the apparent level of water remains the same. It is the same with chemical reactions. Imagine a reversible chemical reaction: A <-> B The speed at which A gets converted to B would be v(forward)=k(forward)[A] At the same time, we lose some product because it gets converted back to A. The speed at which B gets converted to B would be v(reverse)=k(reverse)[B] In equalibrium, the two rates are the same. Therefore we can say: v(forward)=v(reverse) k(forward)[A]=k(reverse)[B] k(forward)/k(reverse)=[B]/[A], which is the equilibrium constant, K. It is useful for many chemical calculations, and a general definition is: for a reaction a A + b B -> c C + d D, the equilibrium constant K=([C]^c*[D]^d)/([A]^a*[B]^b).

WL
Answered by Wojciech L. Chemistry tutor

2883 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

"A chromium compound contains 28.4% sodium and 32.1% chromium by mass, while the rest is oxygen. What is the empirical formula of this compound?"


What is meant by an ion being 'polarising' - and how does that determine if something is ionic/covalent?


Write a half-equation for the overall oxidation of ethanol into ethanoic acid.


How will a catalyst affect the position of equilibrium?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning