Solve: 3x + 4 = x + 12

In this algebraic problem, we are faced with two unknowns (x's) on both sides of the equation. Remember that what we do to one side, we must also do to the other side. So to tackle this, we will first focus on the x's involved in the question. In order to get the x's on one side, we will subtract the x on the right hand side, and therefore we will also do this to the right hand side: = 3x + 4 = x + 12 becomes 3x -x +4 = x - x +12 We are then left with this: = 2x + 4 = 12 We will now deal with the 4 on the left hand side of the equation. Again we will subtract this from both sides as shown below: = 2x + 4 - 4 = 12 - 4 becomes 2x = 8 = x = 8 / 2 and therefore the anser is: x = 4

TF

Related Maths GCSE answers

All answers ▸

How do you differentiate x^2?


Solve algebraically the simultaneous equations: 6m + n = 16 and 5m - 2n = 19


Solve this simultaneous equations, clearly showing all of your workings: x^2 + 2y =9, y - x = 3


In a sale, an item originally worth £140 is reduced by 15%. What is the new price of the item ?