[equ1] 3y − 6x = 3 [equ2] y y x 2 − x + 2 2 = 2
Firstly start by rearranging [equ1] to get y = 2x + 1 . Then substitute this result into [equ2] this will give you (2x + 1) (2x ) x . Simplify the equation and subtract two from both sides to 2 − x + 1 + 2 2 = 2 get an ordinary quadratic equation 4x x . Following on from this utilise the quadratic 2 + 3 − 1 = 0 formula x = . After using this equation the values for are . Then use the 2a −b±√b −4ac 2 x x =− 1, x = 4 1 rearranged form of [equ1] to find the values of y . Which, after evaluation, are y =− 1, y = 2
AS
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