A ladder 6·8m long is leaning against a wall. The foot of the ladder is 1·5m from the wall. Calculate the distance the ladder reaches up the wall.

We have a right angle triangle in this problem. We can use Pythagoras' theorem - the square of the hypotenuse is equal to the sum of the squares of the other two sides of the right angle triangle. We will denote the distance the ladder reaches up the wall as 'h'. Therefore:

1.52 + h2 = 6.82 ;

h= 6.82 - 1.52 ;

h = (6.82 - 1.52)0.5 ;

h = 6.6m

Answered by Mohan V. Maths tutor

2863 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 2x-3y = 24 and 6x+2y = -5


Solve the equations y = x + 1 and y = x^2 - 3x + 4 simultaneously.


Simplify 8x-3+6x


Solve 2x+y=6, 3x+2y=3 for x and y.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences