A ladder 6·8m long is leaning against a wall. The foot of the ladder is 1·5m from the wall. Calculate the distance the ladder reaches up the wall.

We have a right angle triangle in this problem. We can use Pythagoras' theorem - the square of the hypotenuse is equal to the sum of the squares of the other two sides of the right angle triangle. We will denote the distance the ladder reaches up the wall as 'h'. Therefore:

1.52 + h2 = 6.82 ;

h= 6.82 - 1.52 ;

h = (6.82 - 1.52)0.5 ;

h = 6.6m

MV
Answered by Mohan V. Maths tutor

3831 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

f(x) = x^2 + 4x − 6 f(x) can be written in the form (x + m)^2 + n. Find the value of m and the value of n.


What is the highest common factor of 24 and 90?


Solve the following equation by factorisation: x^2 - 2x -15 = 0


I feel really nervous about time pressure in the exam, I don't think I'll finish


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning