The triangle is a right angled triangle with hypotaneuse y, and sides are 7 and 10. The angle θ is between the hypotaneuse and the side of length 10 (I do have a diagram) For question 1: Using Pythagoras’ Theorem you have c^2 = a^2+b^2 (would draw a diagram) Therefore, y^2 = 10^2 + 7^2 y^2 =100+49 y= √149 y = 12.21 For question 2: Using SOHCAHTOA you have the edge opposite to the angle and the edge adjacent to it, therefore you use tan(θ) = Opposite/Adjacent. Therefore, tan(θ)= 7/10 θ = inverse of tan ( 7/10) θ = 34.99 degrees