What are the roots of y=x^2+5x+6 ?

Roots = where line touches x-axis. Set equation equal to 0 as y=0 at the x-axis. Now we need to solve for the x values at which y=0. Quadratic is now 0=x^2+5x+6. Factorise quadratic: 0=(x+3)(x+2). Now you can divide the zero by either (x+3) or (x+2). Both are possibilities and cannot be ignored. Hence two equations are 0=x+3 and 0=x+2. Rearrange now to find that x=-3 and x=-2 when y=0. You have now found the roots of the equation.

Answered by Sam W. Maths tutor

5282 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

When and how do I use the product rule for differentiation?


How can functions be transformed?


Differentiate y=sin(x)*x^2.


Given that y=π/6 at x=0 solve the differential equation,dy/dx=(e^x)cosec2ycosecy


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences