y = 4x / (x^2 + 5). Find dy/dx.

We use the quotient rule here which states that if y = f(x)/g(x) then dy/dx = (f'(x)g(x) - g'(x)f(x)) / (g(x)^2). Here f(x) = 4x and g(x) = x^2 + 5, so we have f'(x) = 4 , g'(x) = 2x. This gives us dy/dx = (4(x^2 + 5) - 2x(4x)) / ((x^2 + 5)^2) = (4x^2 + 20 - 8x^2) / ((x^2 + 5)^2) = (20 - 4x^2) / ((x^2 + 5)^2).

Answered by Patrick S. Maths tutor

9689 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Use Simpson's rule with 5 ordinates (4 strips) to find an approximation to "integral between 1 and 3 of" 1/sqrt(1+x^3) dx giving your answer to three significant figures.


How to integrate e^(5x) between the limits 0 and 1.


I've been told that I can't, in general, differentiate functions involving absolute values (e.g. f(x) = |x|). Why is that?


Lorem ipsum dolor sit amet


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences