Solve the following equations x^2-2x+4=0, x^2+4x+1=0

x2-2x+4= (x-2)(x-2)=0  x=-2 (double root)  

x2+5x+1=0

x1,2= -5+_ (52-4(1)(1) )0.5/2 

x1=4.8     x2=-0.2 (to 1 d.p.)

KF
Answered by Kyriakos F. Maths tutor

3038 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2 - 5x - 14 = 0


Answer quadratic equation in the simplest surd form/ exact from. 5-2x-x^2=0


A ball of mass m is thrown with velocity of (7i + 4j) m/s from a height of 1m. After some time it hits the ground. Find the: a) ball's maximum height b) speed it hits the ground c) distance travelled


How many past papers should i do before the exam?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences