Solve the following equations x^2-2x+4=0, x^2+4x+1=0

x2-2x+4= (x-2)(x-2)=0  x=-2 (double root)  

x2+5x+1=0

x1,2= -5+_ (52-4(1)(1) )0.5/2 

x1=4.8     x2=-0.2 (to 1 d.p.)

Answered by Kyriakos F. Maths tutor

2888 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Suppose we have a circle whose radius is 5cm. If a sector of this circle has an area of 15 cm^2, what is the size its angle (in degrees)?


Solve algebraically the simulations equations: x^2+y^2=25 and y-3x=13


solve this equation: 4(x-5)=x+7


simplfy x/3 + x/4


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences