Solve the following simultaneous equations: 4x+y=10 and 2x-3y=19

To begin to solve this question, we need to re-arrange the equations presented so they both appear in terms of 3y=. This will allow us to get a value for y and thus a value for x. First re-arrange the first equation into the form y=10-4x. From here, times both sides of the equation by 3 (not changing the fundamental relationship between any of the terms) to give us 3y=30-12x. We then rearrange the second equation into analogous terms, getting 3y=2x-19. By then replacing 3y in the first equation with its value in the second equation we get 2x-19=30-12x. We then add 12x and 19 to both sides, giving us 14x=49. From this we get x=3.5 and by plugging this into our equations, we get y= -4.

Answered by Hugh W. Maths tutor

8536 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A t-shirt is in two shops, both of which has it on sale. In shop A, the t-shirt originally cost £15, but has been reduced by 30%. In shop B, it used to cost £17 and has been reduced by 40%. In which shop is the t-shirt now cheaper, and by how much?


How do I solve 7x – 8 = -3x + 2?


Calculate the length of the hypotenuse of a right-angled triangle when the other two sides measure 6cm and 9cm.


How do I draw a straight line graph given a y=mx+c equation by the table method?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences