How do I draw a graph, y = mx + c, if I am only given m and a point that the line passes through?

Let's say we have the equation y = 2x + c and we are told that the line passes through the point (3, 4).  Our first step is to use the numbers from the point (3, 4), by substituting them into our equation. Like so: 4 = 2(3) + c (We have changed the y to 4 and the x to 3). Next all we need to do is solve this equation to find c. 4 = 6 + c, c = -2. And we are done.

AD
Answered by Alex D. Maths tutor

2747 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

f(x) = (x+1)^2 and g(x) = 2(x-1); Show that gf(x) =2x(x+2)


How can I solve equations like 2x + 3 = 8x + 21?


Simplify fully: (24 - √ 300)/(4√ 3 - 5). Give your answer in the form a√ b where a and b are integers and find the values of a and b.


Solve 2x+y=6, 3x+2y=3 for x and y.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences