Find dy/dx for y=5x^3-2x^2+7x-15

Step 1: To differentiate an equation there is a simple rule to follow. For y=axn dy/dx=anxn-1. so for an example y=x3, dy/dx=3x2. Therefore we just apply this rule into our equation.

Step 2: Break the equation down and do each factor of x seperately so 5x3 differentiates into 15x2, -2x2 differentiates to -4x, 7x differentiates to 7 and the 15 disappears from the end. This happens as the 15 just tells us where the line crosses the y axis and therefore has no bearing on the gradient.

Step 3: Put the differentiated parts back together to give the differentiated equation

dy/dx=15x2-4x+7

MT

Related Maths A Level answers

All answers ▸

Differentiate y=x^2cos(x)


y = x*(x-2)^-1/2. Prove dy\dx = (x-4)/2*(x-2)^3/2


Solve the following equation: 5x - 1 = 3x + 7


Line AB has equation 6x + y - 4 = 1. AB is perpendicular to the line y = mx + 1, find m.