Solve the following pair of simultaneous equations 1)x+3y=11 2)3x+y=9

Rearrange equation 2 to make y the subject, then substitute the y expression into equation 1 and collect like terms: 3x+y=9 -->> y=9-3x x+3y=11 -->> x+3(9-3x)=11 -->> x+27-9x=11 -->> 27-11=8x -->> 16=8x -->> 16/8=x -->> x=2 Now that the x term is determined this value can be substituted into either equation 1, equation 2 or the rearranged equation 2 (the rearranged equations is ideal in this case since y is the subject and the then re-arrange is done all we need to do is substitute in the x term): y=9-3x -->> y=9-(3*2) -->> y=9-6 --> y=3 Answer: (2,3)

Answered by Tutor94832 D. Maths tutor

6539 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you find the gradient of a straight line?


FIRSTLY: John has a slice of pizza in the exact shape of an isosceles triangle. 2 sides measure Y + 5 and 1 side measures Y – 2. Write an expression for the total perimeter. SECONDLY: Multiply out the following brackets: (3Y + 8)(3Y + 2)


Find dy/dx for the following equation: f(x) = x^7 + 7x


Triangle ABC is a triangle with a right angle at vertex B. Length BC = 6cm and angle A = 30 degrees. How long is length AC?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences