Solve the following pair of simultaneous equations 1)x+3y=11 2)3x+y=9

Rearrange equation 2 to make y the subject, then substitute the y expression into equation 1 and collect like terms: 3x+y=9 -->> y=9-3x x+3y=11 -->> x+3(9-3x)=11 -->> x+27-9x=11 -->> 27-11=8x -->> 16=8x -->> 16/8=x -->> x=2 Now that the x term is determined this value can be substituted into either equation 1, equation 2 or the rearranged equation 2 (the rearranged equations is ideal in this case since y is the subject and the then re-arrange is done all we need to do is substitute in the x term): y=9-3x -->> y=9-(3*2) -->> y=9-6 --> y=3 Answer: (2,3)

Answered by Tutor94832 D. Maths tutor

6963 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Work out 2 and 3/4 x 1 and 5/7 Give your answer as a mixed number in its simplest form.


The equation of a straight line is 3x + 2y = 24. Find where the line crosses the x-axis.


I'm struggling with approaching questions in Maths, I just don't know where to start. What should I do?


A = {multiples of 5 between 14 and 26}. B = {odd numbers between 14 and 26}. List the members of A∪B and A∩B.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences