Solve the simultaneous equation 2x-4y=8 and 3x+3y=-15

Set 2x-4y=8 as equation 1, and 3x+3y=-15 as equation 2. Multiply equation 1 by 3 and equation 2 by 4 so they look like 6x-12y=24 and 12x+12y=-60. Now add the two equations and you get 18x=-36 or x=-2. Substitute this back into equation 2 and you get -6+3y=-15. Add 6 to both sides and you get 3y=-9 or y=-3.

Answered by Daniel L. Maths tutor

2883 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve equations with unknowns in the denominators?


Solve the simultaneous equations: 5x + y =21 and x - 3y = 9.


Solve 2x+1=11


Kelly is trying to work out the two values of w for which 3w - w^3 = 2 Her values are 1 and -1 Are her values correct? You must show your working.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences