make a the subject of p = (3a+5)/(4-a)

so step 1) remove the denominator by multiplying (4-a) by p. Therefore obtaining p(4-a) = 3a+5. step 2) multiply out to get 4p-ap = 3a+5 step 3) have all the a's on one side, and non a's on other side. therefore: 4p-5 = 3a+ap step 4) factor out the a's. 4p-5 = a(3+p) step 5) make a = (4p-5)/(3+p) 

JW
Answered by Jamie W. Maths tutor

9639 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Given that x(a+bx)(a-bx)=25x-4x^3, what is the value of b^(-a)? a,b>0


In a class there are 57 students. Of these 32 study Spanish, 40 study German and 12 students study neither. How many students study Spanish but not German?


Solve algebraically the simultaneous equations x^2 + y^2 = 25 and y - 3x = 13


V= 4(h^3 +1)^0.5 - 4, find dv/dh when h=2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences