Given that the equation of the curve y=f(x) passes through the point (-1,0), find f(x) when f'(x)= 12x^2 - 8x +1

Firstly, Integrate the f'(x) equation by raising the power by 1 and then dividing by the new power and adding a constant c. This gives you f(x)=(12x^3)/3 -(8x^2)/2 + x + c Then you simplify, f(x)=4x^3 -4x^2 + x + c Insert your y and x values to find c, 0= 4(-1) - 4(1) -1 + c Therefore c= 9 and f(x)= 4x^3 -4x^2 + x + 9

Answered by Daniel M. Maths tutor

13031 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Make x the subject of the equation: 5x+1 = 2-4x


show that y = (kx^2-1)/(kx^2+1) has exactly one stationary point when k is non-zero.


Solve the differential equation dy/dx = 6xy^2 given that y=1 when x=2.


Using first principles find the differential of x^2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences