Solve the simultaneous equations for x and y: 2x+4y=-12 and y=-x-2

From the question we have y = -x - 2 so we can sub in -x-2 everywhere there is a y in the first equation.

The equation is then 2x+4(-x-2) = -12 expanding the brackets we get -2x-8=-12 which you can then rearrange to get x=2.

Finally we must remember to find the value for y as well, we can use the value for x we just found and sub it ino either equation.

Subbing into the 2nd equation we get y=-2-2 so y=-4 

Answered by Daniel G. Maths tutor

3119 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 3x^2 - 4x - 6 = 0.


Solve algebraically the simultaneous equations x^2 + y^2 = 25, y – 3x = 13


Factorise 5x^2 + 20x


A GCSE is graded out of 140 marks. 1/5 of these marks were given for coursework. The rest were divided between two reading and listening tests, with the marks split in the ratio 3:4 respectively. How many marks were given for the reading test?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences