Solve the simultaneous equations for x and y: 2x+4y=-12 and y=-x-2

From the question we have y = -x - 2 so we can sub in -x-2 everywhere there is a y in the first equation.

The equation is then 2x+4(-x-2) = -12 expanding the brackets we get -2x-8=-12 which you can then rearrange to get x=2.

Finally we must remember to find the value for y as well, we can use the value for x we just found and sub it ino either equation.

Subbing into the 2nd equation we get y=-2-2 so y=-4 

Answered by Daniel G. Maths tutor

3206 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The equation of the line L1 is y = 3x – 2. The equation of the line L2 is 3y – 9x + 5 = 0. Show that these two lines are parallel.


How do I solve a pair of simultaneous equations?


L1: y=3x-2 & L2: 3y-9x+5=0, show these two lines are parallel


6y+2x^2=6 x=(y+1)^0.5 solve the simultaneous equations


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences