Find the area under the curve y = sin(2x) + cos(x) between 0 and pi/2

to find the area integrate the function between 0 and pi/2:

indefinite integral of y = -1/2 cos(2x) + sin(x) + c

ignore c and input boundary conditions:

[-1/2 cos(pi) + sin(pi/2)] - [-1/2 cos(0) + sin(0)] = [1/2 + 1] - [-1/2 + 0] = 2

Answered by Harry D. Maths tutor

6518 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the coordinates of the turning point of y=e^(2x)*cos(x)?


Given that y = 5x^2 - 4/(x^3), x not equal to 0, find dy/dx.


Solve the following integral: ∫ arcsin(x)/sqrt(1-x^2) dx


What is the equation of a curve with gradient 4x^3 -7x + 3/2 which passes through the point (2,9)?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences