How can you find the coefficients of a monic quadratic when you know only one non-real root?

We know that non-real roots appear in complex conjugate pairs. Hence when we know one root, we know both of them. Then, as we can factorise a quadratic in it's linear factors, we know our quadratic is a constant times the product of x minus the roots. Lastly, as our quadratic is monic, we must have that this constant is 1. Then find the coefficients by expanding the brackets.

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Line AB has equation 4x+5y+2=0. If the point P=(p, p+5) lies on AB, find P . The point A has coordinates (1, 2). The point C(5, k) is such that AC is perpendicular to AB. Find the value of k.


The polynomial p(x) is, p(x)= x3-5x2-8x+48.Use the Factor Theorem to show that (x + 3)is a factor of p(X)