Solve x^2=4(x-3)^2

To solve this equation we need to expand the right hand side to get: x^2 = 4(x^2-6x+9), then we multiply whats in the bracket by 4 to get: x^2 = 4x^2 - 24x +36. We can subtract x^2 from both sides to give: 3x^2 - 24x +36=0. Now all 3 terms are divisible by 3 so the equation simplifies to: x^2 - 8x +12=0, we can factorise this to get: (x-2)(x-6) = 0, therefore x = 2 or x = 6. 

Answered by Kelsi F. Maths tutor

4259 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

When do I use the sin rule and when do I use the cosine rule?


How would you solve a simultaneous equation?


There are 200 students in Year 10 110 are boys. There are 250 students in Year 11 140 are boys. Which year has the greater proportion of boys? (Taken from Nov 2014 AQA Unit 2)


How do I know when a quadratic function crosses the y-axis?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences