Solve x^2=4(x-3)^2

To solve this equation we need to expand the right hand side to get: x^2 = 4(x^2-6x+9), then we multiply whats in the bracket by 4 to get: x^2 = 4x^2 - 24x +36. We can subtract x^2 from both sides to give: 3x^2 - 24x +36=0. Now all 3 terms are divisible by 3 so the equation simplifies to: x^2 - 8x +12=0, we can factorise this to get: (x-2)(x-6) = 0, therefore x = 2 or x = 6. 

Answered by Kelsi F. Maths tutor

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