Solve x^2=4(x-3)^2

To solve this equation we need to expand the right hand side to get: x^2 = 4(x^2-6x+9), then we multiply whats in the bracket by 4 to get: x^2 = 4x^2 - 24x +36. We can subtract x^2 from both sides to give: 3x^2 - 24x +36=0. Now all 3 terms are divisible by 3 so the equation simplifies to: x^2 - 8x +12=0, we can factorise this to get: (x-2)(x-6) = 0, therefore x = 2 or x = 6. 

KF
Answered by Kelsi F. Maths tutor

5279 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Benjamin has a 0.7 chance of passing his driving test the first time and a 0.85 chance of passing the second time. What is the probability of his passing on either the first or second try?


3 teas and 2 coffees have a total cost of £7.80 5 teas and 4 coffees have a total cost of £14.20 Work out the cost of one tea and the cost of one coffee.


Samuel had 3 piles of coins, I, II and III. Altogether there was 72p. Pile II had twice as much as pile I. Pile III had three times as much as pile II. How much money was in Pile III?


How do I form an algebraic fraction into a single fraction in its simplest form?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning