Solve the simultaneous equations: 2x-y=x+4; x^2+4y^2=37

taking equation 1 and solving for x: 2x-y=x+4 x-y=4 x=y+4 Sub our new equation into equation 2 from the question: (y+4)2 +4y2=37 Expand and simplify: y2 +8y+16+4y2=37 5y2+8y-21=0 Factorise: (5y-7)(y+3)=0 therfore y= 1.4; -3 Sub into our simplest equation to get an x value: x=5.4, y=1.4 x=1, y=-3

Answered by Alexander W. Maths tutor

4660 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve: 3^(x^2-5x+2)=9^(x+1)


Solve the equation 18x^2-3x=6


Factorise 3x^2 + 14x + 8


Factorise 3x^3y^2-6x^2y+9xy


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences