Solve the simultaneous equations: 2x-y=x+4; x^2+4y^2=37

taking equation 1 and solving for x: 2x-y=x+4 x-y=4 x=y+4 Sub our new equation into equation 2 from the question: (y+4)2 +4y2=37 Expand and simplify: y2 +8y+16+4y2=37 5y2+8y-21=0 Factorise: (5y-7)(y+3)=0 therfore y= 1.4; -3 Sub into our simplest equation to get an x value: x=5.4, y=1.4 x=1, y=-3

AW
Answered by Alexander W. Maths tutor

5792 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Differentiate sin(x)cos(x)


1. a) the equation of a line is y=A^x. A is the point where the line intersects the y axis. Find A. then Q15 https://revisionmaths.com/sites/mathsrevision.net/files/imce/1MA1_3H_QP.pdf


How do I solve simultaneous equations?


How do you solve the #EdexcelMaths question?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning