Solve the simultaneous equations: 2x-y=x+4; x^2+4y^2=37

taking equation 1 and solving for x: 2x-y=x+4 x-y=4 x=y+4 Sub our new equation into equation 2 from the question: (y+4)2 +4y2=37 Expand and simplify: y2 +8y+16+4y2=37 5y2+8y-21=0 Factorise: (5y-7)(y+3)=0 therfore y= 1.4; -3 Sub into our simplest equation to get an x value: x=5.4, y=1.4 x=1, y=-3

AW
Answered by Alexander W. Maths tutor

5449 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand the following quadratic (x+3)(2x-2)


How do I find the roots and and coordinates of the vertex of the graph y = 2x^2 + 4x - 8 ?


what is half of five-eights as a percentage?


The area of a square is 49cm^2. The perimeter of the square is equal to the circumference of a circle. Work out the radius of the circle. Give your answer to 1 decimal place.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning