Answers>Maths>GCSE>Article

Solve the simultaneous equations: 2x-y=x+4; x^2+4y^2=37

taking equation 1 and solving for x: 2x-y=x+4 x-y=4 x=y+4 Sub our new equation into equation 2 from the question: (y+4)²+4y²=37 Expand and simplify: y²+8y+16+4y²=37 5y²+8y-21=0 Factorise: (5y-7)(y+3)=0 therfore y= 1.4; -3 Sub into our simplest equation to get an x value: x=5.4, y=1.4 x=1, y=-3

Answered by Alexander W. • Maths tutor

6160 Views

See similar Maths GCSE tutors

Solve the simultaneous equations: 2x-y=x+4; x^2+4y^2=37

Related Maths GCSE answers

If you are given the function f(x) = 10-3x and g(x) = (x-3)/2 , find the value of the composite function gf(4) ?

How do you factorise a quadratic?

Express the recurring decimal 0.21313... as a fraction.

Solve the simultaneous equations 4x + 2y =20 and 8x + 6y =45