Solve the simultaneous equations: 2x-y=x+4; x^2+4y^2=37

taking equation 1 and solving for x: 2x-y=x+4 x-y=4 x=y+4 Sub our new equation into equation 2 from the question: (y+4)2 +4y2=37 Expand and simplify: y2 +8y+16+4y2=37 5y2+8y-21=0 Factorise: (5y-7)(y+3)=0 therfore y= 1.4; -3 Sub into our simplest equation to get an x value: x=5.4, y=1.4 x=1, y=-3

Answered by Alexander W. Maths tutor

4528 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 5x + 3y = 9 and 7x - 2y = 25.


Make y the subject of the equation: t=(y+2)/(4-y)


There is a Wheel of Fortune. The Wheel is numbered 1-15. Each section is equal in size. If the spinner lands on your number you win a prize. Ali has the number 6. What is the probability that he wins a prize? Give answer as percentage to 2 d.p


Solve this pair of simultaneous equations (1) 5x+2y=20 and (2) x+4y=13


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences