X~Binomial (n,p) with n= fixed number of independent trials and p= probability of a trail succeeding.
X ~Binomial can be approximated to Y~ Normal if:
1) The number of trials, n, is large
2) Probability of succeeding in a trial , p, is close to 0.5
Step 1: Apply continuity correction
If given P(X=>n) then P(Y=>n-0.5)
P(X>n) then P(Y>n+0.5)
P(X<=n) then P(Y<n+0.5)
P(X<n) then P(Y<n-0.5)
Step 2: Find mean and variance of Y~Normal
For X, we know the mean= np and variance = np(1-p)
So Y~Normal(np, np(1-p)
Step 3: Standardise Y~Normal to the standard normal
Values given in statistical tables for the normal distribution are based on the standard normal Z~Normal(0,1)
Z= (Y-np)/ sqrt(np(1-p))= m
Step 4:
Using the table find the desired probability relating to value, m, of Z and this approximates to probability relating to n of X
P(Z<=m) = probablity corresponding to m in the table
P(Z=>m) = 1- P(Z<=m)
P(Z<-m)= P(Z=>m) = 1- P(Z<=m)
P(Z>-m)= 1-P(Z<-m)= 1-(1- P(Z<m)= P(Z<m)
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