Differentiate the following equation: y = 2(x^3) - 6x

Firstly we look at the term 2(x^3). The power of x (in this case 3) is multiplied by the factor of x (in this case 2) and the power is then reduced by 1. This means it is 2x3(x^{3-1}) which simplifies to 6(x^2) This process is repeated for the second term in the sequence which is -6x. The power of x is 1 so when multipled by -6 it stays as -6. The power of x is reduced by 1 which makes it x^0. Anything to the power of 0 is 1 so the term -6x becomes -6. Below is the working out written mathematically: y = 2(x^3) -6x dy/dx = 6(x^2) - 6 dy/dx = 6(x^2 -1)

Answered by Anna W. Maths tutor

3175 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Circle C has equation x^2 + y^2 - 6x + 4y = 12, what is the radius and centre of the circle


Find the gradient of y=x^2-6x-16 at the point where the curve crosses the x-axis


Simplify (􏰀36x^−2)􏰁^ 0.5


How do you intergrate sin^2(x)?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences