June 2008 C1 Paper Differentiation Question
a) ask student: purpose of differentiation (i), how to perform differentiation (ii) (i) to find the gradient of a curve (ii) multiply the coefficient of x by its indice then minus one from the indici perform this calculation to get dy/dx = 3kx^2 - 2x + 1 b) three steps: 1st: find dy/dx of C at A in terms of k: dy/dx = 3/4k + 2 2nd: find dy/dx of the new equation: dy/dx = 7/2 3rd: equate the two equations: 3/4k + 2 = 7/2 -> k = 2 c) now we know k, we can insert k and x-coordinate at A back into original equation to find y value y = -6
NG
Related Maths A Level answers
All answers ▸y=20x-x^2-2x^3. Curve has a stationary point at the point M where x=-2. Find the x coordinate of the other stationary point of the curve and the value of the second derivative of both of these point, hence determining their nature.
Given that y=4x^3-(5/x^2) what is dy/dx in it's simplest form?
if f(x) = 7x-1 and g(x) = 4/(x-2), solve fg(x) = x
The equation x^3 - 3*x + 1 = 0 has three real roots; Show that one of the roots lies between −2 and −1