differentiate y = 4x^3(12e^-4x) with respect to x

y = 4x3e-4x   u = 4x3  v = e-4x du/dx = 12x2 dv/dx = -4e-4x using the product rule; vdu +udv  vdu + udv = 12x2e-4x - 16x3e-4x

Answered by Lewis M. Maths tutor

3219 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Using the sum, chain and product rules, differentiate the function f(x) = x^n +x^3 * sin(1/[3x])


Simplify (􏰀36x^−2)􏰁^ 0.5


Find the exact value of the gradient of the curve y = e^(2- x)ln(3x- 2). at the point on the curve where x = 2.


A curve has the equation y=x^3+2x+15. Find dy/dx.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences