The gradient of a curve is defined as Dy/dx = 3x^2 + 3x and it passes through the point (0,0), what is the equation of the curve

Integrate this = (3x^3)/3 + (3x^2)/2 + c So y = x^3 + (3x^2)/2 + c Using point (0,0), 0 = 0 + 0 + c so c = 0. Full equation of the curve is therefore x^3 + (3x^2)/2

Answered by Laura T. Maths tutor

5447 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

C2 differentiate 2x^2 -3x +4 with respect to X


Find f''(x), Given that f(x)=5x^3 - 6x^(4/3) + 2x - 3


The quadratic equation 2x^2 + 6x + 7 = 0 has roots A and B. Write down the value of A + B and the value of AB


Find 1 + (1 + (1 + (1 + (1 + ...)^-1)^-1)^-1)^-1


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences