Given the function f(x) = (x^2)sin(x), find f'(x).

The function f(x) is a product of 2 functions of x, so when we differentiate it, we need to use the product rule.

The product rule states that for a function f(x) = g(x)*h(x), f'(x) is given by g(x)*h'(x) + h(x)*g'(x).

If we break f(x) up into two parts and let g(x) = x2 and h(x) = sin(x) then we can find g'(x) and h'(x).

We find that g'(x) = 2x and h'(x) = cos(x). Substituting these values into the product rule, we get:

f'(x) = x2cos(x) + 2xsin(x).

Answered by Jason S. Maths tutor

8322 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is 'grouping' and how does it work?


How do you integrate ln(x)?


Differentiate with respect to X: x^2 + 2y^2+ 2xy = 2


Calculate the indefinite integral of ln(x)?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences