The equation of a circle is x^2-6x+y^2+4y=12. Complete the square to find the centre and radius of the circle.

When we complete the square, we're looking for an equation that looks like (x-a)2 + (y-b)2 = r2, where (a,b) is the centre and r is the radius. When we expand brackets using FOIL, the x part is (x2-2ax+a2). This means the term with x in it has a coefficient of 2a. Therefore halving it will give us a! So let's apply this to our equation. The x term has a coefficient of -6 and the y term has a coefficient of +4. Dividing these by 2 we get -3 and 2. So the centre is (-3,2)! Now since (-3)2=9 and (2)2=4 we can add these on two complete the squares: x2-6x+9-9 + y2+4x+4-4=12 (x-3)2-9 + (y+2)2 -4 = 12 (x-3)2 + (y+2)2 = 25 (x-3)2 + (y+2)2 = 52 So the radius is 5!

Answered by Hubert A. Maths tutor

4034 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the values of x that satisfy the following inequality 3x – 7 > 3 – x


Given f(x) = (x^4 - 1) / (x^4 + 1), use the quotient rule to show that f'(x) = nx^3 / (x^4 + 1)^2 where n is an integer to be determined.


Differentiate: f(x)=2(sin(2x))^2 with respect to x, and evaluate as a single trigonometric function.


Find the acute angle between the two lines... l1: r = (4, 28, 4) + λ(-1, -5, 1), l2: r = (5, 3, 1) + μ(3, 0, -4)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences