Use integration by parts to integrate ∫ xlnx dx

∫ u(dv/dx) dx = uv − ∫ v(du /dx)dx is the Integration by Parts formula. 

If you set u=lnx, differentiation (rememeber from tables) leads to du/dx= 1/x, and dv/dx=x and so v=x^2/2 (raise power by one then divide by that).

Plugging this into the equation, f(x)=(x^2/2)lnx- ∫(x^2/2)/x dx, just taking the RHS integral -> 1/2∫x dx = x^2/4 +C and so combining all of this f(x)=(x^2/2)lnx-x^2/4 +C. 

Answered by Minty M. Maths tutor

15733 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What does it mean to differentiate a function?


log3 (9y + b) – log3 (2y – b) = 2, Find y in terms of b.


Integrate, with respect to x, xCos3x


Solving a quadratic with ax^2 e.g. 2x^2 - 11x + 12 = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences