Use integration by parts to integrate ∫ xlnx dx

∫ u(dv/dx) dx = uv − ∫ v(du /dx)dx is the Integration by Parts formula. 

If you set u=lnx, differentiation (rememeber from tables) leads to du/dx= 1/x, and dv/dx=x and so v=x^2/2 (raise power by one then divide by that).

Plugging this into the equation, f(x)=(x^2/2)lnx- ∫(x^2/2)/x dx, just taking the RHS integral -> 1/2∫x dx = x^2/4 +C and so combining all of this f(x)=(x^2/2)lnx-x^2/4 +C. 

MM
Answered by Minty M. Maths tutor

21689 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What's the gradient of the curve y=x^3+2x^2 at the point where x=2?


Find dy/dx if y=(x^3)(e^2x)


An object of mass 2kg is placed on a smooth plane which is inclined at an angle of 30 degrees from the ground. Calculate the acceleration of the object.


Find the equation of the tangent to the curve y=x^3 + 4x^2 - 2x - 3 where x = -4


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning