Solve these simultaneous equations, 2x+y=6 and 3y-x=11

First step is to choose between the three methods for solving simulataneous equations; elimination, substitution and eqaulity. In this case the best method is probably substitution, but personal preference is reasonable.  By rearranging the second equation to find an expression for x we get; x=3y-11. Substituting this into the first equation gives 2(3y-11)+y= 6y-22+y=7y-22=6. Add 22 to both sides for 7y=28 and hence by dividing both sides by 7, we obtain y=4.  Substitute this into either equation and solve, eg, 2x+4=6 gives x=1. Therefore the solution is x=1 and y=4.

EG
Answered by Edward G. Maths tutor

5208 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise 3a^2 - 9a


The equation of line L1 is y = 3x-2 and the equation of line L2 is 3y-9x+5 = 0. Show that these two lines are parallel.


Solve the simultaneous equations 3x +y =11 and 2x+y=8


The first floor of an ancient japanese tower has 150 steps. Each floor above has 5 fewer floors than the previous. So, the second floor has 145 steps, the third 140 etc. How many floors does the tower have if the final floor has 30 steps leading to it.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning