P=(3a+5)/(4-a) Make a the subject

P=(3a+5)/(4-a)First of all we need Get rid of the denominator, we do this by multiplying both sides by (4-a)This leaves P(4-a)=3a+5 (as any term multiplied by the denominator leaves only the numerator)The next step is to expand the bracket, which leaves us with 4P-aP=3a+5.Now we need to put all "a" terms on one side of the equation and all "non a" term on the other. To do this we can add aP to both sides and minus 5 to both sides. This leaves us with 4P-5=3a+aP.Now we have a as a common term on the right side so we can factorise to move a outside of the bracket leaving 4P-5=a(3+P)Now the final step is to divide both sides by (3+P) to leave a as the subject.This leaves us with the final correct answer of (4P-5)/(3+P)=a

Answered by Joshua S. Maths tutor

3866 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve simultaneous equations? eg 1) 4x = 16 - 2y and 2) 3x + y = 9


Jorgen has 20 sweets in his pocket. The sweets are either blue or yellow. He picks a sweet and eats it and takes another sweet and eats it again. The probability of him picking two blue sweets is 6/30. How many yellow sweets does he have in his pocket.


A rectangle has the side lengths root6m and root3m, what is the area of the rectangle in its simplest form.


Expand (x+3)(x+6)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences