P=(3a+5)/(4-a) Make a the subject

P=(3a+5)/(4-a)First of all we need Get rid of the denominator, we do this by multiplying both sides by (4-a)This leaves P(4-a)=3a+5 (as any term multiplied by the denominator leaves only the numerator)The next step is to expand the bracket, which leaves us with 4P-aP=3a+5.Now we need to put all "a" terms on one side of the equation and all "non a" term on the other. To do this we can add aP to both sides and minus 5 to both sides. This leaves us with 4P-5=3a+aP.Now we have a as a common term on the right side so we can factorise to move a outside of the bracket leaving 4P-5=a(3+P)Now the final step is to divide both sides by (3+P) to leave a as the subject.This leaves us with the final correct answer of (4P-5)/(3+P)=a

Answered by Joshua S. Maths tutor

3489 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I factorise quadratic equations?


Solve (x + 2)(x+3) = (2x+4)


rearrange c=(4-d)/(d+3)


Solve the simultaneous equations. 3x + 5y = 1 , 2x - 3y = 7


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences