Use the substitution u=x^2-2 to find the integral of (6x^3+4x)/sqrt( x^2-2)

First use the substitution to find du/dx which is 2x. From this we now know that dx= du/2x (just re-arranging.) Substituting that into the integral we now get (6x3+4x)/ (sqrt (u) x 2x) du. Cancelling out the 2x we now have (3x2+2)/ sqrt (u) du. This is equal to (3u+8)/ sqrt(u) du using the original definition of u. This is equal to 3u0.5+ 8u-0.5 du. Integrating this we get 2u1.5 + 16u0.5+ c and to get the final answer we just substitute for u.

KS
Answered by Khalil S. Maths tutor

8996 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The curve y = 2x^3 -ax^2 +8x+2 passes through the point B where x = 4. Given that B is a stationary point of the curve, find the value of the constant a.


Integrate xsin(x) with respect to x


A particle of mass m moves from rest a time t=0, under the action of a variable force f(t) = A*t*exp(-B*t), where A,B are positive constants. Find the speed of the particle for large t, expressing the answer in terms of m, A, and B.


Find an expression in terms of powers of cos(x) for cos(5x)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences