Use the substitution u=x^2-2 to find the integral of (6x^3+4x)/sqrt( x^2-2)

First use the substitution to find du/dx which is 2x. From this we now know that dx= du/2x (just re-arranging.) Substituting that into the integral we now get (6x3+4x)/ (sqrt (u) x 2x) du. Cancelling out the 2x we now have (3x2+2)/ sqrt (u) du. This is equal to (3u+8)/ sqrt(u) du using the original definition of u. This is equal to 3u0.5+ 8u-0.5 du. Integrating this we get 2u1.5 + 16u0.5+ c and to get the final answer we just substitute for u.

Answered by Khalil S. Maths tutor

8900 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is a 'derivative'?


Where does the circle (x-6)^2+(y-7)^2=4 intersect with y=x+3


Find the equation of the normal to the curve 2x^3+3xy+2/y=0 at the point (1,-1)


A function f is defined by f(x) = x^3 - 3x^2 + 1. i) Write down f'(x). ii) Hence find the co-ordinates of the stationary points of the curve y=f(x).


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences