Solve the equation 3^(2x+1)=1000

We can use logarithms with base 3 to solve this equation.2x+1=log310002x=log3(1000)-1x=0.5(log3(1000)-1)x=2.64

Answered by Samuel D. Maths tutor

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Simultaneous Equations


dx/dt = -5x/2, t>=0. Given that x=60 when t=0, solve the differential equation, giving x in terms of t.


Simplify (7+sqrt(5))/(sqrt(5)-1), leaving the answer in the form a+b*sqrt(5)


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