Using Newton's law of universal gravitation, show that T^2 is proportional to r^3 (where T is the orbital period of a planet around a star, and r is the distance between them).

Newton's law of gravitation is: FG=(GMm)/(r2).First of all, it's a good idea to draw a diagram of the planet and star, labelling the directions of the centripetal force and and the planet's velocity in particular, along with anything else that helps visualise the question. We know that the equation for centripetal force is FC=mω2r (from circular motion). Since this centripetal force FC and the gravitational force FG point in the same direction (from the planet to the star), we can equate them!
This gives us: (GMm)/(r2) = mω2rSubstituting in ω=2π/T, we get: (GMm)/(r2) = (4π2mr)/(T2)We can see that the two 'm's cancel out, and the 'r's combine to make r3.Do a bit of rearranging: T2 =(4π2r3)/(GM)There it is! T2 is proportional to r3; this is known as Kepler's 3rd Law of planetary motion.

Answered by Jake B. Physics tutor

3128 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Explain how and why the diffraction pattern of electrons passing through a slit depends on their momentum.


What height do geostationary satellites orbit above the Earths surface?


How to we work out the speed of an object at a certain point in its trajectory?


Why are fringes are formed in the Young double slit experiment?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences