Acid HA has a Ka of 2.00 x 10-4mol dm-3. A solution was made by adding 15cm3 of 0.34 M NaOH to 25cm3 of 0.45M HA. Calculate the moles and the concentration of A- and HA in this solution. Using the expression for Ka calculate the pH of the solution

Write the equation: NaOH + HA --> NaA + H2O. Find the moles of A-: the moles of A-= the moles of NaOH added. 15 x 10-3 x 0.34= 5.10 x 10-3. Workout the initial moles of HA: 25 x 10-3 x 0.45= 0.01125 (the values are given in the question above). Workout the moles of HA remaining (as it has reacted): 0.01125-0.00510= 6.15 x 10-3. Workout the concentration of A-: there are 0.00510 moles in the solution (15+25=40cm3). To work out the concentration 5.10 x 10-3 x 1000/40= 0.1275 M. Workout the concentration of HA: using the 6.15 x 10-3 mole that we were remaining, the calculation is as follows 6.15 x 10-3 x 1000/40= 0.1538 MKa= [H+] [A-]/[HA]=2.00 x 10-4 mol dm-3. We have the following information: Ka= 2.00 x 10-4 mol dm-3, HA=0.1538M and A-=0.1275. We need to rearrange the above equation to Ka [HA]/[A-] and substitute in the numbers so we have 2.0 x 10-4 x 0.1538/0.1275=2.41 x 10-4. Workout the pH: -log (2.41 x 10-4) =3.62

Answered by Hibba S. Chemistry tutor

6105 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

State the relative charge and relative mass of a proton, of a neutron and of an electron. In terms of particles, explain the relationship between two isotopes of the same element. Explain why these isotopes have identical chemical properties.


What is the trend in atomic radius of the elements across Period 3 and why does this occur?


How does temperature affect the position of equilibrium if the reaction is exothermic?


Explain the bonding and thus the properties of a carbon allotrope


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences