Differentiate y=3x^2+2x+4 and find the stationary points, decide if it is a local maximum or minimum.

First Differentiate the equation to getdy/dx=6x+2Equal this to 0 to find the stationary pointdy/dx=0=6x+2 => 6x=-2=> x=-2/6=> x=-1/3
differentiate again to find the whether it is a maximum or minimumd²y/dx²=6Therefore as 6>0 we have that this point is a minimum.