Solve 3x^2 + 13x + 14 = 0
Firstly, you need factorise.a = 3 b = 13 c = 14Find 2 numbers which add to make b(13) and multiply to make ac(42). These numbers are 6 and 7You can now split up the x coefficient to: 3x^2 + 6x + 7x + 14. You can now factorise each "half" to get to: 3x(x+2) + 7(x+2)Factor out "x+2" to get (3x+7)(x+2) = 0So the solutions are x = -7/3 or x = -2
CW
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