Solve the equations x^2+y^2=13 and x-2y=1 simultaneously.

Rearranging the second equation gives x=2y+1. Substituting this into equation 1 gives (2y+1)2+y2=13.Rearrangingthis and factorising the quadratic equation gives (5y-6)(y+2)=0, givingsolutions of y=6/5 and y=-2.Thecorresponding x values are found by substituting these values into equation 2giving: x=17/5 and x=-3 respectively.

Answered by Phoebe S. Maths tutor

8383 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify 3(x-5)/x^2-3x-10


Work out the points of intersection of the graphs of y= (x+2)(x-4) and y=3x+6.


Find the value of x in the equation x^2 - 2x + 1 = 0


How do I know whether to add or minus in Pythagoras's theorem?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences