How do you solve the simultaneous equations x^2+y=1 and -x+y=-1

First rearrange the second equation so that it's equal to y. You do this by adding x and y to both sides of the equation. You should then have y=x-1. Next you should sub y=x-1 into the first equation, x2+y=1. You should now be left with x2+x-1=1. This can be rearranged by subtracting 1 from each side to create the quadratic equation x2+x-2=0. This can be solved in which ever way you prefer; I would factorise it, leaving you with (x+2)(x-1)=0. Therefore x=-2 or x=1

CM

Related Maths GCSE answers

All answers ▸

How do you find the equation of a circle?


The area of a square is 49cm^2. The perimeter of the square is equal to the circumference of a circle. Work out the radius of the circle. Give your answer to 1 decimal place.


Solve the simultaneous equations: 2x + y = 18, x - y = 6


solve the simultaneous equations 3x+7y=18 and 7x+9y=8