To solve this question we need to find the values of x which work for the equation x^(2) + 4x + 4 = 0. To solve the equation we can factorise the left-hand side into brackets which will multiply together to form x^(2) + 4x + 4. x^(2) + 4x + 4 can be rearranged to (x+2)(x+2). Therefore the solutions to (x+2)(x+2)=0 are when each of the brackets are equal to zero because any number times 0 is zero. Solving x+2=0 we can see there is only one, repeated, value of x which satisfies the equation which is x=-2.