250x10^-3= 0.25g dm-3sulfate mr x moles = mass0.25 x 3/10 = 0.075 g sulfatemr sulfare = 32 + (4 x 16) = 96moles sulfate = 0.075/96 = 7.8125 x10-4Per equation above: moles SO42-= moles Ba2+ Concentration= Moles/Volume[Ba2+] = 7.8125x10-4/0.2=3.91x10-3 mol dm-3