Chlorine, 15 g, is contained in a vessel with a volume of 0.80 dm3 at 330 K. Calculate the pressure exerted when the chlorine is treated as a perfect (ideal) gas giving your answer in terms of kPa
PV=nRT V=0.8 dm3=0.8 x 10-3 m3P= nRT/V R= 8.31 J K-1mol-1 T= 330 K n= mass/mr n = 15 g/ (2x35.5 g mol-1) n = 0.212 mol P = (0.212 mol x 8.31 J K-1mol-1 x 330 K)/ 0.8 x 10-3 m3P= 726000 Pap=726 kPa
HG
